Sun, 2012-05-13 19:18
Hello
I have attached a part of my code that I am having difficulty getting to work.
I am reading a field from my database to see if a link to an image is present, and if it is, then I want to display the image.
If not, then I have some code that allows the user to draw in their signature.
I thought my code would work, but it isn't showing up.
Thanks
<br/> <table border="0" class="table-inner"> <tr> <td width="10"> </td> <td width="160"> <!-- (2) INITIAL - DAMAGES --> <?php $sQuery = "SELECT * FROM signatures WHERE `web-order-num` = \"$sWebOrderNum\" "; $iResult = mysql_query ($sQuery); $iRow = mysql_fetch_assoc($iResult); $sTempDmg = $iRow["initial-damages"]; if (strlen($sTempDmg) > 0) { $sTempImg = IMAGE_PATH . $sTempDmg; print ("<img src='$sTempImg' />"); } else { ?> <div id='ctlSignatureDamages_Container' style='width:130px;height:50px;margin:0px;'> <script language="javascript" type="text/javascript"> var ieVer = getInternetExplorerVersion(); if (isIE) { if (ieVer >= 9.0) isIE = false; } if (isIE) { document.write("<div ID='ctlSignatureDamages' name='ctlSignatureDamages' style='width:130px;height:50px;border:Dashed 2px #DDDDDD'; z-index:9999'></div>"); } else { document.write("<canvas ID='ctlSignatureDamages' name='ctlSignatureDamages' width='130' height='50'></canvas>"); } </script> </div> <?php } ?> </td> <td align="left" valign="top"> <b><u>Damages (Pets & Kids) (initial at left)</u></b> <br/> Our Company holds no responsibility for damage in and around the work site. Please keep kids and animals inside or away from our active work site.<br/> We will inform you of the scheduling. </td> <td width="10"> </td> </tr>
[Moved, as not a css question. ~gt/mod]